{"stem":"विहगान्तर","iast":"vihagāntara","found":true,"koshas":2,"places":[{"kosha":"NSKS","kosha_title":"नानार्थार्णवसंक्षेप","kosha_latn":"Nānārthārṇavasaṃkṣepa","ref":"6.45","page":"0029","kind":"artha","gender":null,"doubtful":true,"verse":["अङ्गारकस्तु ना भौमे द्वयोस्तु विहगान्तरे ।","अश्मन्तकं तु नप्स्त्रीत्वे चुल्ल्यां वृक्षान्तरे तु ना ॥ ४५ ॥"],"metre":"anustubh","metre_status":"full","flags":[],"url":"https://kosha.sanskrit.site/k/NSKS#NSKS.6.0.311","head":"अङ्गारक"},{"kosha":"SRMS","kosha_title":"शब्दरत्नावली","kosha_latn":"Śabdaratnāvalī","ref":"7.32.13","page":"0294","kind":"artha","gender":null,"doubtful":true,"verse":["गुरौ तुरगभेदे स्याद्भूधरविहगान्तरे ।","हासो रसे च हसने हिंसा तु घातचौर्ययोः ॥"],"metre":null,"metre_status":"none","flags":[{"rule":"metre","found":"anustubh · pāda 2 syl. 2 ध (sub) pāda 4 syl. 3 तु (sub)"}],"url":"https://kosha.sanskrit.site/k/SRMS#SRMS.7.32.13","head":"हंस"}],"truncated":false,"source":"Vidyāsthāna Kośa, https://kosha.sanskrit.site"}